+ 1

Can someone tell me what’s wrong?

My code should work by trying to find a name(input) in the list, and output an according message, but it only works for the first name on the list. https://sololearn.com/compiler-playground/ckXXGoBVN3jg/?ref=app

5th May 2024, 7:01 PM
underlineyou
2 Antworten
+ 7
Presently, there is a break statement in both branches of the if/else, so the loop never advances to the next element. There is an easy fix to make it do exactly what you need. Convert the if/else into a for/else by reducing the indentation of the else clause and removing its break statement. for name in name_database: print("Searching...") if name == search: print("Found!") break else: #<--- unindent print("Not found :(") #<--- unindent #break <--- remove In a for/else statement, the else clause executes if and only if the for loop finishes without encountering a break statement.
5th May 2024, 8:32 PM
Brian
Brian - avatar
+ 7
# Hi, underlineyou ! # You can use this solution as a hint for how to solve the problem more easily. name_list = ["Jhon" , "Mary" , "Peter" , "Paul", "Louie"] name = input().title() print("Searching...\n...\n...") if name in name_list: print(f"\t-> {name} found in list!") else: print(f"\t-> {name} not found in list :(")
5th May 2024, 8:34 PM
Per Bratthammar
Per Bratthammar - avatar