to find the smallest integer using while loop

Answer 1

create a variable for the smallest number (int smallest = arrayThings[0];) assign it to the first thing in the list/array, then literate through the list/array and have an if statement comparing the the current smallest variable and the indexed one if the indexed is smaller then assign the smallest variable (if (smallest > arrayThings[current iteration]){smallest = arrayThings[current iteration];}) whatever the indexed one was until it is over and the smallest variable should contain the smallest item in the list p.s I'm pretty sure this would work better as a for loop and I am sorry for my messy comment

Answer 2

lol praveen u r hilarious

Answer 3

#include <iostream>
using namespace std;

int main() {
int arr[4] = {1,2,0,4};
int arr_len = 4;
int sm_nu = arr[arr_len];

while(arr_len) {
arr_len --;
sm_nu = arr[arr_len] > sm_nu ? sm_nu : arr[arr_len];
}

cout<<"smallest number: "<<sm_nu <<endl ;
return 0;
}

Answer 4

0