How the output of these code is 4??? I had asked these questions in challenge.

Question

int i;
for(i = 0; i < 3; i+= 2){}
System.out.print(i);

Answer 1

In the for loop...
Initially i=0
then i=i+2(i becomes 2)
condition is still satisfied as i<3(I.e 2<3)
then again i=i+2(means 2+2=4)
now it checks whether i<3 or not and as it is not the loop terminates , therefore i=4 is the final value of i which is printed by System.out.print()

Answer 2

Make It Yourself...
I think my explanation was not clear.
Well as I mentioned earlier i inside the loop was 2 the condition is valid , now see in next iteration it got incremented by 2 that means it becomes 4. Now notice that i=4 is greater than 3 which isn't valid , so it is not accepted, that's why the loop terminates and the final value of i is 4 only.

Answer 3

Observe that the system.out.println is not inside the for loop. Tha is why when the loop is finished the i=4 and then it is printed.

Answer 4

Observe also that the counter is i+=2 not i++ .

Answer 5

thanks ,now I have no query kueen indian

Answer 6

but kueen indian i want to be less than 3 so how 4 is accepted

Answer 7

It is not accepted in the for loop,because it is not < 3 but that doesnt change the fact that the value of i=4