why double x =10/4 gives 2 ?

Question

int x =10/4 gives 2 OK.
But why double x =10/4 gives 2 ?
why should I run double x =10/4.0 to get 2.5 ?

Answer 1

C# will evaluate first the operation after the equal sign, where we have 10/4. 10 it's an integer and 4 it's an integer and the result will be an integer 10/4 = 2. After this it will cast the result(an integer) to a double (because x it's a double) and we will have 2.0, and in the output 2.0 will be 2. If we have one member or bouth from the right a double (10.0/4, 10/4.0 or 10.0/4.0) then the result of the operation from the right of the equal sign will be considered a double not an integer, because in this cases where we have double(10.0)/integer(4) the int will be automatically cast to double by the program.

Answer 2

I guess, I need to think that first operation is 10/4. Result is 2. After, second operation is double and it double 2 gives 2. I think it should give 2.0??

Answer 3

You should write: double x = (double)10/4; It will tell the compiler that 10 is a double and thus it will evaluate the result as a double.

Answer 4

Maybe it should be: Console.WriteLine( {0}, ((double)x%y));
Did not check if it works this way.

Answer 5

10 and 2 are of type int, so the result is of type int.

Answer 6

Because you should enter one of the number with kind 10.0 or 2.0

Answer 7

Any remainder is dropped of to return a integer value

Answer 8

as @Gighi said "C# will evaluate first the operation after the equal sign" hence the result will be 2.

you can try as following to make sure result is 2.5
i.g:
double y , x;
y = 10;
x = 4;

Console.Write(y/x);

Outputs: 2.5

Answer 9

is there an option where you can modify the int to a double directly in the writeline parenthesis without modifying the rest of the code? console.writeline(double{0};x%y)?

Answer 10

simply,when double is not mentioned (before 2)it gives approximate value....

Answer 11

because 10/2 =5

Answer 12

(x)