+ 4

int A :: b; what does this instruction mean?

the above code is declared below a class 'A' and b is the data member of the class A.

22nd May 2017, 12:39 PM
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5 Antworten
+ 10
:: is the scope resolution operator. It's used to access and initialize static class or namespace members.
22nd May 2017, 1:28 PM
Karl T.
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+ 5
Because that's the default value.
22nd May 2017, 1:37 PM
Karl T.
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+ 2
class A { public: static int b; }; int A::b; int main() { A x; cout << x.b; } i get the out put has '0' but i didnt declare the value for b then how? and what does " int A: b; " mean in this program?? also i just started learning c and c++😅
22nd May 2017, 1:22 PM
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+ 2
@ helioform yeah i can get it but i have not initialized the value of 'b' anywhere then how does it print the value has "0".
22nd May 2017, 1:35 PM
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- 3
A::b mean A derive class, b base class.. did you really read and learn the C++ course ?
22nd May 2017, 12:54 PM
Mugfirfauzy Siregar
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