Percentage grade to letter grade. I'm having trouble with my code. This is only the begining of my code. Help please. I

Question

grade = (input())

grade = 100

if grade >= 90 and grade <= 100:
print('a')

if grade >= 80 and grade <= 89:
print('b')

Answer 1

You might need to cast your input to integer and also use "elif" in the if statement.

Answer 2

You might want to try ternary statements here:

if 80 <= x <= 89:
block_of_code

That keeps the code more concise.

Answer 3

Make your code public. It's easy to help like that.

Answer 4

I debuged it,

The text needs work.

edit

I deleted the old post, its code was wrong

https://code.sololearn.com/cYIMEBTrlWVL/?ref=app

Answer 5

@Kuba Thank you,

I did not know,

that is was possible put statements together like that.

Answer 6

still getting an error

Answer 7

thank you everyone