Why does Java not support operator overloading ?

Answer 1

Java only allows arithmetic operations on elementary numeric types. It's a mixed blessing, because although it's convenient to define operators on other types (like complex numbers, vectors etc), there are always implementation-dependent idiosyncrasies. So operators don't always do what you expect them to do. By avoiding operator overloading, it's more transparent which function is called when. A wise design move in some people's eyes.

Answer 2

ask from creator of java.

use kotlin it support operator overloading

Answer 3

That's not an answer