In C++ I want to take input 1 for even number output and input 2 for odd number output. How I limit input to user.

Question

I made a program, which give all even numbers from (1-100) after giving output any number. I want to limit input to 1. How can I do this.

Answer 1

See the project I made here. It limits the users choices to what is available in the store

https://code.sololearn.com/cVsqivdibVH0/#cpp

Example
int numberOfAction = 4;
int userInput;

if (!(std::cin >> userInput)) {
std::cout << "Not a number.\n\n";
std::cin.clear();
std::cin.ignore(9999, '\n'); }
else if (userInput - 1 < 0 || userInput > numberOfActions) {
std::cout << "That was not between 0 - " << numberOfActions << "\n\n";
std::cin.clear();
std::cin.ignore(9999, '\n');
}
else if (userInput > 0 || userInput < numberOfActions) {
std::cin.clear();
std::cin.ignore(9999, '\n');

}
}

Answer 2

@parker; mmhmm that was on purpose as the program I took it from had 0 for exit, so it (0) had its own if clause which i deleted as the example was already verbose. But yes. The above example does disclude 0. Good Spot!

Answer 3

@jay, there's a small error in that example, the first "else if" statement will execute if the input is 0, making it necessary to be between 1-4, and not 0-4 as said in the output, and the last else if statement will execute no matter what, because of the "||".