overloading why output B ?

Question

class A {
public void do() {
System.out.println(''A'');
}
public void do(String str) {
System.out.println(str);
}
}
class B {
public static void main(String[ ] args) {
A object = new A();
object.do(''B'');
}
}

Answer 1

This is how it works:

You have 2 same methods. One is void method, without any parameters to take and other is void method with parameters.

When you call method from class A (object.do("B"); You use method which requires some value in parameter and then prints the value, you have entered.

If you would write object.do(); without giving any value in parameters, program would use the method, which doesn't require any parameters.

Hope it's all clear and I helped you.

Answer 2

wot

Answer 3

B