Why <?php $a = 2; $b = $a++; echo $a; ?> is a=3 and b=3

Question

I don't understand the result in this exercise.
Result: $a=3, $b=3

Answer 1

a=3 but b=2
because in $b=$a++ first b is set to the value of a , then a would be incremented. here you should know the difference of pre-increment and post-increment

Answer 2

$a is 3 but i think $b is 2

Answer 3

Thanks 👍