Simplify :(A+C). (A+A. D)+A. C+C

Question

plz solve this question

plzz anybody help

Answer 1

(a+c)(a+ad)+ac+c
= aa+aad+ac+acd+ac+c
= a(a+ad+2c+cd)+c
= a(a(1+d)+c(2+d))+c
but ... I do not really know what you are aiming for ...

Answer 2

Thank u

Answer 3

=AA+AAD+AC+ACD+AC+C
=AA(1+D)+AC(1+D+1)+C
=AA+AC+C

Answer 4

Can you explain last and second step transition please ? It seems wrong to me @Shade96 :/

Answer 5

=(AA+AAD)+(AC+ACD+AC)+C
=AA(1+D)+AC(1+D+1)+C
*I factor out (AA) it remain (1+D) and also factoring out AC from second parentheses
=AA+AC(2+D)+C
*logically (1+D)=1 (Boolean algebra theorem) it remain 1*AA which is equal AA
And about second term, yes I made a mistake thank you for warning me
@Baptiste

Answer 6

He never said it was Boolean !

Answer 7

So what is it -_-!

Answer 8

Numbers maybe :p

Answer 9

=AA+AAD+AC+ACD+AC+C
=AA(1+D)+AC(1+D+1)+C
=AA+AC+C
=A+C(A+1)
=A+C

LAST EXPRESSION

Answer 10

Ans. (A+ C) (A+AD) + AC + C

(A + C)A+ AC+ C

A+ AC+ AC + C

A+C