+ 1

I have been trying to understand this for the past 5 days. But couldn't.. i mean i never get even one percent of pythons

dunders and operator overloading... a little help could be appreciated and thankful. class Vector2D: def __init__(self, x, y): self.x = x self.y = y def __add__(self, other): return Vector2D(self.x + other.x, self.y + other.y) first = Vector2D(5, 7) second = Vector2D(3, 9) result = first + second print(result.x) print(result.y)

28th Aug 2017, 5:34 PM
stephen haokip
stephen haokip - avatar
3 Antworten
+ 3
The code created a class whose name is "Vector2D" that contains 2 variables x and y and a method for addition that adds x's together and y's together then the code created 2 variables which are named "first" and "second" and assigned different values to each of them then added them using the addition method that is explained before I wish that could help you
28th Aug 2017, 6:03 PM
Mohammed Hany
Mohammed Hany - avatar
28th Aug 2017, 6:20 PM
HelloWorld
0
When you do "a+b", what really happens is that Python itself tries to call "a.__add__(b)". If there is that method, great, use that answer. If there isn't, it then tries to call "b.__radd__(a)". If there is not, it throws an error (I don't remember which one, might be a TypeError, but I'm not sure).
29th Aug 2017, 3:29 AM
Amaras A
Amaras A - avatar