Int y; for(y=1;y<=5;y+=3) cout <<y; почему отсюда выходит output 7?

Question

help me

Answer 1

The output should be 14.

y = 1.
y <= 5 is true.
Output: 1

y += 3 is 4.
y <= 5 is true.
Output: 4

y += 3 is 7.
y <= 5 is false.
So, cout doesn't run.

I suggest reviewing the for loop in the course.
If there are no brackets the first statement in the code is considered inside the loop.

Answer 2

l think as you,but this programme gives 7!!!really amazing

Answer 3

put this in compiler and you saw the same

Answer 4

У Вас, скорее всего, перед cout где то фигурные скобки спрятались.