Function overloading - weird number returns when return is not provided. what is this number?

Question

int sum(int a, int b=23)
{
int result = a*b;
return(result);

}
int sum(double a, int b=23)
{
cout << "second func"<<endl<<a<<endl;
//no operation no return
}
int main()
{
cout<<"sum with double as parameter "<<endl<<sum(2.01f)<<endl;
}

Output:
second func
2.01
sum with double as parameter
4757824

where is the number 4757824 coming from?

also when i use
float sum(double a, int b=23)
{
cout << "second func"<<endl<<a<<endl;
//no operation no return
}
and passing 2.01 as argument for 'a'
i am not getting 25.01 as output, what am i missing?

Answer 1

Your bestestest friend: Undefined behaviour.

https://stackoverflow.com/questions/3459810/how-do-c-progs-get-their-return-value-when-a-return-is-not-specified-in-the-f

Answer 2

.. because you are referencing an unitialized value when you remove the return statement from sum

int sum() should return an integer, if it returns nothing a random value is accessed from that memory location

it is in effect the same as doing:
int a;
cout << a;

Answer 3

Use double instead float

Answer 4

https://code.sololearn.com/cqbd2v6Vidmi/?ref=app

Look at this

Answer 5

If you do not intend to return an intager your code should be
"void sum(prarams) {... }