How to calculate number of 1s in a binary number?

Answer 1

public class IntegerToBinary {

public static void main(String[] args) {

int x = 102;

int cnt=0;

String y = Integer.toBinaryString(x);

System.out.println("Binary conversion is: " + y);

for (int i=0; i<y.length();i++)

{

if (y.substring(i, i+1).equals("1"))

{

cnt =cnt+1;

}

}

System.out.println("1's are: " + cnt);

//one more way

cnt=0;

char[] z = y.toCharArray();

for (int i=0; i<z.length;i++)

{

if (Character.toString(z[i]).equals("0"))

{

cnt =cnt+1;

}

}

System.out.println("0's are : "+cnt);

}

}

Answer 2

haha I mean in assembly language

Answer 3

how about in java. I just want to know how it works.

Answer 4

public class solution{
public static void main(String arcs[]){
string binnumber = Integer.toString(100,2);
//converting 100 into binary
int count = 0;
for(int i=0; i<binnumber.length(); i++){
String c = Character.toString(text.charAt(i))
if(c.equals("1"))
count++;
}
System.out .println(count);
}
}

Answer 5

use a calculator

Answer 6

1s ?
Um....Can you tell me the thing you confused :)?(Becus some word you use I'm falling in confused too)
If I can give advice I will

Answer 7

I am a bit confused.. For example, x=5, print number of 1s =2

Answer 8

Ok I think he help you for now

Answer 9

yea he is