python func open() doesn't see the file in directory

Question

py 3
guys,the file really in same directory where .py located is
please,don't blame me if the code contains rly stupid mistakes
THANK YOU GOD BLESS YOU
CODE:

filename = open('input1.txt')
filename.replace(" ","\n")
file = filename.read()
filename.close()
l=len(file)
a=file.readline()
a.replace("\n","")
X=int(a[0])
N=int(a[1])
T=int(a[2])
t=240
u=N-X
z=u*T
g=t/z
print(str(int(g)))

Answer 1

What I mean is that the variable filename is the file handler. It does not have a .replace() method.
If you get the "file not found" error, I can think of three things:
- either the file is indeed not there
- it is there, but has a 'hidden' attribute
- you run the python script command from a different path and it can't find the file

Try adding (at the very beginning, before the code you wrote):

import os
print(os.listdir())

That should list you the files it sees in the current directory. If you can't see the 'input1.txt' file there, nor can your script.

Answer 2

What kind of error you get?

Answer 3

Hmmm... I would assume that filename.replace won't work, as it's a string method not file object method.
Doesn't the parser let you know which line the error is located in?

Answer 4

i got FileNotFoundError

Answer 5

i don't know how to use parser for py yet
can you please tell me more about "filename.replace won't work"??