my code was for (f=1;f<=num1&&f<=num2;f++) { if (num1%f==0&&num2%f==0) cout<<"the gcd is"<<f; how can i printed the last val. f

Question

how can i print the last value of f.
example the number is 12 and 8 ..i want to display the gcd is 4.
but in my program it was displaying like this
the gcd is 1
the gcd is 2
the gcd is 4

how can i printed the highest value of f.

Answer 1

A quick and simple way would be to create a variable before the loop, assign the value in the loop and print it after the loop.

Answer 2

I'm on my phone so can't really type code.

Before the loop: int highestFactor=0
In the loop, after the if condition: highestFactor=f
After the loop: cout << "highest common factor is " << f

Answer 3

int gcf(int a, int b) {
if (b == 0)
return a;
return gcf(b, a&b);
}

this is a more elegant, recursive function for finding the Greatest Common Factor, if it's useful to this application. you could then make a Least Common Denominator function that calls gcf:

int lcd(int denomA, int denomB) {
int GCF = gcf(denomA, denomB);
return (denomA * denomB) / GCF;
}

Answer 4

example code please

Answer 5

thanks

Answer 6

nothing changed on the code