Error in program . please remove error

Question

#include <iostream>
using namespace std;

int main() {
int n;
cin>>n;
switch(n){
case 1.1:cout<<n*1.1;break;
case 5.6:cout<<n*5.6;break;
default:cout<<n;
}
return 0;
}

Answer 1

floating point value is not allowed in switch multiply x by 10 and use case 11: and case 56

Answer 2

ya you cant use floating point in switch

Answer 3

try case 11 and 56 .. after multiplying x by 10

Answer 4

you cant use point in switch statement ... to solve this problem we multiply the number by 10 or 100 or 1000 depending upon the number of digits after the point
eg:

cin<<n;
n*=10;
switch(n){
case 11: ...;break;
case 56:....;break;

i am not that good at explaining stuff .. hope your doubt is clear nw

Answer 5

any time

Answer 6

good one @kenAc

Answer 7

float n

Answer 8

Freeze I agree with you

Answer 9

Freeze I agree with you

Answer 10

nice explain thanks @zaid

Answer 11

More detailed solution:

#include <iostream>
#include <cmath> // needed for round

using namespace std;

int main(){
float n;
int i_n; //needed for switch case

cin >> n;
i_n= round(n*10);

// Testoutput
cout<<"n= "<<n<<"\ni_n= "<< i_n<<endl;

switch(i_n){
case 11: cout << n*1.1; break;
case 56: cout << n*5.6; break;
default: cout << n;
}

return 0;
}

Answer 12

//Shortversion of upper code

#include <iostream>
#include <cmath> // needed for round

using namespace std;

int main(){
float n;
cin >> n;

switch((int)round(n*10)){
case 11: cout << n*1.1; break;
case 56: cout << n*5.6; break;
default: cout << n;
}

return 0;
}

Answer 13

if i do not use int n

Answer 14

float n ; // giving error :'(

Answer 15

well i want to call case 1.1 or 5.6 then what i did ?

Answer 16

11 and 56 is another option.

Answer 17

float cant be used in switch as you said okay then i replaced 1.1 and 5.7 to 11 and 56 respectively . if i want to call case 11 how ?

Answer 18

thanks @kenAc

Answer 19

N has a type of integer, you switch-case loop checks for float type of N.