Y does the pointer shows 88 even after getting deleted?

Question

#include <iostream>

int main(){

int *pointer = new int;

*pointer = 88;

std::cout << "*Pointer : " << *pointer << std::endl;
delete pointer;
std::cout << "*Pointer : " << *pointer << std::endl;

return 0;

}

Answer 1

Thank you Mr.JPM7 for pointing out to this new standard facility.

Answer 2

You need to nullify your pointer.

delete pointer;
*pointer = 0;

and not (since you'd use it on the next cout - otherwise you should use the below instead of *pointer = 0)

// pointer = 0;

// Access violation reading location 0x00000000.
std::cout << "*Pointer : " << *pointer << std::endl;