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Help is needed there how do I solve?

ax^2+6x+c=0

15th Oct 2017, 11:07 AM
Jman
Jman - avatar
5 Antworten
+ 11
it's in the form of ax²+bx+c=0 which is a quadratic equation. The solution to this is given by: x = (-b±√(b²-4ac))/2a here b=6 so... x = (-6±√(36-4ac))/2a which can be simplified to... x= (-3±√(9-ac))/a Hope this answers your question =)
15th Oct 2017, 11:14 AM
Mayur N Mallya
Mayur N Mallya - avatar
+ 10
The value(s) of x what you get above after using the equation is the roots of the equation. write this equation in Fortran programming language and make it print the value(s) of x.
15th Oct 2017, 11:39 AM
Mayur N Mallya
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0
thnx
15th Oct 2017, 11:18 AM
Jman
Jman - avatar
0
it says, using Fortran as language program to obtain the root of quadratic equestion "ax²+bx+c=0"
15th Oct 2017, 11:21 AM
Jman
Jman - avatar
0
thanks again
15th Oct 2017, 11:54 AM
Jman
Jman - avatar