Not knowing the reason of the answer found in challenge

Question

$a = 'e';
$b = '2';
echo $a + $b;
the output for this is 2. Can someone tell me the reason please?

Answer 1

It is because non-numerical parts of a string have no integer value.
Hence, "e" is as good as "0"
Edit: If a number is wedged between letters, it is considered non-numerical too

Answer 2

I am not so good in PHP so I verified ut on code playground

Answer 3

Glad it helped :)

Answer 4

thanks for the info Pegasus

Answer 5

you do your best 👍👍👍