+ 3
E=(X+y^2):27+x^y
3 Antworten
0
What do you want to know with this?
0
Take a look at RPN (reverse polish notation) and Shunting Yard algorithm. They should help you solve this.
0
#include <iostream>
using namespace std;
int main() {
long double x;
long double y;
long double result;
cin >> x;
cin >> y;
result = (x+y^2)/27+x^y;
cout << result;
return 0;
}