+ 3

E=(X+y^2):27+x^y

29th Oct 2016, 9:59 AM
XOPGAMINGX _300
XOPGAMINGX _300 - avatar
3 Antworten
0
What do you want to know with this?
29th Oct 2016, 10:21 AM
Pablo RG
Pablo RG - avatar
0
Take a look at RPN (reverse polish notation) and Shunting Yard algorithm. They should help you solve this.
29th Oct 2016, 10:43 AM
Daniel Oravec
Daniel Oravec - avatar
0
#include <iostream> using namespace std; int main() { long double x; long double y; long double result; cin >> x; cin >> y; result = (x+y^2)/27+x^y; cout << result; return 0; }
29th Oct 2016, 4:44 PM
Misha Vinokurov
Misha Vinokurov - avatar