The code in the description is working in playground where as it should not because it has mistakes...plz tell me why

Question

<?php
$myArray[0] = "John";
$myArray[1] = "<strong>PHP</strong>";
$myArray[2] = 21;

echo "$myArray[0] is $myArray[2] and knows $myArray[1]";
?>

Answer 1

Because in Php string in double quotes are interpreted: if they contains variable names, they are replaced by their value, so your last line is equivalent to:

echo $myArray[0]." is ".$myArray[2]." and knows ".$myArray[1];

Answer 2

Your question, and almost your problem, is unclear: it works as it should in sololearn code playground... have you problem with trying to use it elsewhere?

Answer 3

( btw i did not write this code, it is an example code from arrays exercise of php course )

Answer 4

why the variable myArray[0] is inside double quote, i thought only strings need double quotes

Answer 5

It's echoing a string. That's what echo does.

Answer 6

dot should be used for string concatenation
and the array value place without double quotation
only the string part must be in double quotation