Anyone pls tell me how to print patterns in c++

Question

Like *. a.
* *. a b
* * *. a. b. c
till 'n' lines
Explanation pls

Answer 1

Answered by Gaurav
buddy i think u shoild try urself first
just notice if u enter n , that means u need n rows ... make a loop for n rows
now every row , see what u have to do ... u see that u need spaces first... make a loop for that ... now what u see is u need to print * ... make a loop for that
//here is the rough view , u need to figure it out yourself ... if u want to make possible patterns by urself ☺
for (){
for (){}
for (){}
}

Answer 2

for i in range(x):
print(' '*(x-i),'* '*i)

Try this.. Works like a charm😀😀
Even i was trying this for a lot of time😂

Answer 3

Idk in c++.. But you'll get the logic..

This will print a simple pattern in python:
x=int(input())
for i in range(x):
print('*' * i)

This will multiply '*' i times for each iteration.. For eg.. When i is 0.. 0 times '*' (nothing)
When i is 1.. 1 times '*'
When i is 2.. Two times '*'.. And so on.. Until i is x..

Try this logic in c++

Answer 4

What?

Answer 5

c++ is not each processed line wise
it will take 3 loops to print the above patterns

Answer 6

@Yash thanks btw

Answer 7

but what about the spaces
Ur code will give output as
*
**
***

Answer 8

See pattern in my question

Answer 9

c++

Answer 10

Use for loops.
for (int i=1;i<=n;i++){
cout<<(n-i)*" "<<i*((" "+"*")

Answer 11

in python it's easy

Answer 12

buddy only in c++

Answer 13

Thanks Verma

Answer 14

actually 3 loops are needed and some logic to set spaces
1st loop goes till n
and then inside that loop another for loop is set for spaces and after that for the another loop for printing

Answer 15

Verma make it pls

Answer 16

Eg.
for(i=0;i<n;i++)
{for(j=0;j<n-i;j++)// this loop is for spaces(focus on the condition)
{cout<<" ";
}
for(k=0;k<=i;k++)//this loop is for printing
{cout<<"*";
}
}
caution: I have made this roughly so it may give imperfect output but see the logic

Answer 17

int main() {int i,j,k,n;
cin>>n;
for(i=0;i<n;i++)
{for(j=0;j<n-i;j++)// this loop is for spaces(focus on the condition)
{cout<<" ";
}
for(k=0;k<=i;k++)//this loop is for printing
{cout<<"* ";
}cout<<endl;
}
//caution: I have made this roughly so it may give imperfect output but see the logic
return 0;
}
this is complete correct code

Answer 18

int main() {int i,j,k,n; char ch;
cin>>n;
for(i=0;i<n;i++)
{ch='a';
for(j=0;j<n-i;j++)// this loop is for spaces(focus on the condition)
{cout<<" ";
}
for(k=0;k<=i;k++,ch++)//this loop is for printing
{cout<<ch<<" ";
}cout<<endl;
}
return 0;
}
This is for the a b c d loop