How it is giving this output

Question

int score = 5;
int *scorePtr;
scorePtr = &score;

cout << scorePtr << endl;

//Outputs "0x29fee8"

Answer 1

& gives the location in memory of the variable, whereas * give the value of the memory location. what you want to do is this

int score = 5;
int *scorePtr = &score;

cout << *scorePtr << endl;

Answer 2

c++ basic tuto
score is a variable with 5 as value
&score is the value's address and his type is a pointer.
cout displays value's address of the pointer.