How to create a function that gets a list filled with strings as an input and then deletes the duplicates

Answer 1

ok, another way:

def uniqList(lst):
newList = list()
for a in lst:
if a not in newList:
newList.append(a)
return newList

if you want to update the old list, just write:
myList = uniqList(myList)
with this function or previous

Answer 2

you can transform your list into set, and then back to list, this will remove duplicates

def uniqList (lst):
return list(set(lst))

Answer 3

i was kinda looking for another way to do it

Answer 4

it works when i dont make the code get the list as an input but when i do get the list as an input the function splits the list into characters and prints something like ["[","a",",","b","c","]"]

Answer 5

do you really giving a list as function argument?
what you write seems to be a string representation of printed list, but it's not a list.
function does what it does but with chars in this string.
you must look for mistakes in you list assigning, maybe it's really a string

Answer 6

Just checked the type and yes it sees it as a string

Answer 7

so the i have a listN=input ("enter your list: ") at start and i give an input like ["abc","bcd","abc","bcd"] what can i do to make it see this input as a list

Answer 8

first, remember this: all you input is a string, so you must convert it to what you need, unless you need a string.
it's easier with numbers, you just use int(input()) or float(input()).
to input a list (of strings, in your case), you must either do it in a loop, appending each input to a list, or input a whole string, dividing elements with specific separator that your strings-elements do not contain.

listN = input() #here it is a string, for example, "abc, def, ghi"
listN = listN.split(", ") #and here it is a list ["abc", "def", "ghi"]

then you can do anything you need