F&A Diskussionen
why does this code output that there is an error because the else statement doesn't have a corresponding if statement?. How do i correct this?
#include <iostream>
using namespace std;
int main() {
int a;
for (int x =0; x<5;x++){
cin>>a;
if (a<1){
cout<<"a cannot be less than 1\n";
}
else if (a>10){
cout <<"a cannot be greater than 10\n";
}
}
else{
cout<<"code can run now"<<endl;
}
return 0;
}
3 Stimmen
8 Antworten
Explain please
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2 Antworten
Output who can explain?
1 Stimme
1 AntwortAnyone help me with this?
0 Stimmen
2 Antwortenint main()
{
int num = 1;
int number;
int total = 0;
while (num <= 5) {
cin >> number;
total += number;
num++;
}
cout << total << endl;
return 0;
}
i neeed a very simple discussion please about the loop i don't understand anything
1 Stimme
3 Antworten
How do you play Code Coach?
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5 Antworten
what is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Stimme
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How can I write cool?
2 Stimmen
4 Antworten
how can we code , like value of a+ value of b,
if sum is 100
how can we put a if statement stating if value < 100 cout you tried hard...sometimes like that ,
I mean to say how can we combine a normal addition and subtraction with if statement.
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help
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WY I get a rundum number from memory when I run this code
#include <iostream>
using namespace std;
int main ()
{
int array [5];
for (int x = 0; x < 5; x++) {
array [x] = 42;
cout << x << ': ' << array [x] << endl;
}
return 0;
}
if I replace ': ' with ": " every thing works well.
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Header file of C++
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