F&A Diskussionen
What is the output and how dose it came ?
#include <iostream>
int main() {
std::cout << (10 & 6) << std::endl;
std::cout << (10 | 6) << std::endl;
return 0;
}
0 Stimmen
3 Antworten
#include <iostream>
using namespace std;
class employee
int main()
{
private:
double salary;
public:
void getsalary(double sal)
{
salary=sal;
}
void display()
{
cout<<"the salary:"<<salary;
}
};
void main ()
{
employee programmer;
employee manager;
manager.getsalary (60000.0);
programmer.getsalary(40000.0);
manager.display();
programmer.display();
return 0;
}
1 Stimme
5 Antworten
How can i make a function that takes two inputs lets say a certain number and an array of numbers and i want the function to return the remainders of dividing the number by the numbers in the array?
1 Stimme
4 Antworten
Functions help please
0 Stimmen
1 Antwort
3 positive integers. Find max. I'm having trouble with the input validation coding and combining it with max code.
0 Stimmen
4 Antworten
How do people hack things?
0 Stimmen
14 AntwortenThis code is supposed to receive users date of birth and output users current age but it's not working
1 Stimme
1 Antwort
JS void keyword?
0 Stimmen
1 Antwort
Javascript restart prog
6 Stimmen
2 Antworten
Given two numbers X and Y, write a function that: 1 returns even numbers between X and Y, if X is greater than Y else it returns
-4 Stimmen
5 Antworten
Can I overload a method by creating methods with the same name but changing both the return type and the parameters? Or does it work only when I change the parameters...
0 Stimmen
2 Antworten
I need an example.
2 Stimmen
1 Antwort
what is it mean that a method reaturn a value or not for example using void to not return a value what it means at deep down of it? what is the big deal ?
0 Stimmen
3 Antworten
Can someone help me please. I can understand the result of the cout << p << endl;
#include <iostream>
using namespace std;
int main() {
int x = 8;
int *p;
p = &x;
cout << *p << endl;
cout << p << endl;
cout << &p;
return 0;
}
1 Stimme
6 Antworten
in the following why the code num=num+1;can't be applied just after while loop in the beginning of curly braces?
#include <iostream>
using namespace std;
int main()
{
int num = 1;
while (num < 6) {
cout << "Number: " << num << endl;
num = num + 1;
}
return 0;
}
0 Stimmen
7 Antworten
In the code below the output is 2. This code is used in a challenge and I get an error when I select the answer 2. It accepts as correct the answer 1 which I believe is wrong. If you agree please thumbs up.
If you find any other errors please post them here!
#include <iostream>
using namespace std;
int main()
{
for(int i=1; i>=1; i++) {
if(i<1 || i>1){
cout << i;
break;
}
}
return 0;
}
8 Stimmen
8 Antworten
What is the output and why?
public static int[] make (int n){
int[]a=new int [n];
a [i]=i+1;
}
return a;
}
public static void dub (int []jub){
for (intent i=0;i <jub.length;i++){
jub*=2;
}
}
public static int mus (int []zoo){
int jus=0;
for (int i=0;i <zoo.length;i++){
jus+=zoo [i];
}
return jus;
}
public static void main (String [] args){
int [] bob =make(5);
dub (bob);
System.out.println (mus (bob));
}
0 Stimmen
2 Antworten
my code is working perfectly as shown on test cases but why is it failing every test case.?
0 Stimmen
3 Antworten
public class MyClass {
public static void main(String[ ] args) {
int num = 5;
addOneTo(num);
System.out.println(num);
}
static int addOneTo(int num) {
num = num + 1;
return num;
}
}
0 Stimmen
2 Antworten
Trig Calculator Help
1 Stimme
4 Antworten
What is return? In Python? It is little bit confusing can u help me guy's by answering my doubt
0 Stimmen
2 Antworten
why does this code output that there is an error because the else statement doesn't have a corresponding if statement?. How do i correct this?
#include <iostream>
using namespace std;
int main() {
int a;
for (int x =0; x<5;x++){
cin>>a;
if (a<1){
cout<<"a cannot be less than 1\n";
}
else if (a>10){
cout <<"a cannot be greater than 10\n";
}
}
else{
cout<<"code can run now"<<endl;
}
return 0;
}
3 Stimmen
8 Antworten
public class Program {
static int div(int a, int b)
{
if(b == 0)
{
throw ArithmeticException("Division by Zero");
} else {
x = a/b;
return x;
}
}
public static void main(String[] args) {
int x= div(42,2);
System.out.println(x);
}
}
what is wrong with this code ..
0 Stimmen
5 Antworten
can anyone plz explain me this program step by step?#include <iostream>
using namespace std;
class MyClass {
public:
int var;
MyClass() { }
MyClass(int a)
: var(a) { }
MyClass operator+(MyClass &obj) {
MyClass res;
res.var= this->var+obj.var;
return res;
}
};
int main() {
MyClass obj1(12), obj2(55);
MyClass res = obj1+obj2;
cout << res.var;
}I am not getting the part inside operator+
0 Stimmen
8 Antworten
Which access modifier explicitly says that a method or variable of an object can be accessed by code from outside of the class o
-2 Stimmen
1 Antwort
"id returned 1 exit status"?
1 Stimme
1 Antwort
Please help with if...return..else
0 Stimmen
1 Antwort
can anyone explain this output?
#include <iostream>
using namespace std;
int x(int &a,int &b)
{
a=3;
b=4;
return a+b;
}
int main()
{
int a=2;
int b=7;
int c=x(a,a);
cout <<a<<endl<<b<<endl<<c;
}
output:-
4
7
8
0 Stimmen
2 Antworten
what is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Stimme
7 Antworten
Heute heiß
New code
1 Votes
Clean Code
3 Votes
How would you solve the part of the C# Intermediate code project that requires operator overloading?
0 Votes
Hello Everyone
0 Votes