F&A Diskussionen
Printing pattern with Javascript
0 Stimmen
1 Antwortcan someone please explain why this code keeps telling me complication error instead of outputting the value of speed.
#include <iostream>
using namespace std;
class myClass {
public:
void setcarspeed (int a){
speed=a;
}
int getcarspeed(){
return speed;
}
private:
int speed;
};
int main() {
myClass obj;
obj.setcarspeed (40);
cout<<obj.getcarspeed ;
return 0;
}
2 Stimmen
3 AntwortenI'm not able to create the new path, I put in the variable path and value c: program files/java/jdk1.80_101 which is what this file is named and it still doesn't work on the command prompt, everytime I put in Javac I get Javac is not recognizable as an internal or external command, operable program or botch file. please help
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4 Antwortenin order to find the sum of n numbers given by user,suppose our program is to find the sum of any 4 numbers given by user (using while loop such that (while(i<=4))and incrementing each value of i by 1),if the user give any 2 inputs instead of four then the total sum should be the summation of that two inputs..but the program shows the sum something else,why it is so??
2 Stimmen
3 AntwortenCan anyone help me to code this
Write a method 'timesTable()' which accepts an integer value num from the keyboard and uses it to print 'times table' of itself in a structured format. Your output must include a header row. For example, if the user enters 5, your program's output should be:
5 Times Table
1 5 5
2 5 10
3 5 15
4 5 20
5 5 25
6 5 30
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5 AntwortenYou shall write a program that reads, from standard input, an arbitrary number of case-insensitive card descriptions, the totality of which shall be considered a hand. When standard input is exhausted, the program shall print one line to standard output describing the value of the hand. The program shall generate no other output.
0 Stimmen
3 Antwortenx = 42;
int num = 0;
while (num <3)
Consele.writeline (x);
num++;
int x = 42; is just an int with an asigned value of 42
int num=0; is what initiate the count for the while loop
while (num < 3); means 0<3 true, 1< 3 true, 2<3 true, the loop end at 2 bc 3 <3 is false
consele.writeline (x) will display 42 while num < 3
num++ will execute and then add 1 to check if the while loop still true, but it stop at 2, bc 3 makes it false.
so the consele.write will write 42 three times. x=42, remember the (x)
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2 AntwortenI have 10 variables called, int1, int2, int 3 and so on. The user can write one number into the console. If the user types 7, I want to add 3 to the value of int7. how do I do this without 10 if statements? can I somehow do something like, (int + "userinput") += 3?
thank you for your help! :D
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2 AntwortenIn the short code below, I declared an array of five elements. But I'm getting confused on how to use it in a while loop. My main question is , if the user inputs a userchoice1 value that is less than 1, I want the code to keep looping until the user inputs a number that is not less than 1. But I don't know if the 7th line (userchoice1 [x]++) shows the right way to loop it.
1 Stimme
2 AntwortenHeute heiร
Help please?
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