F&A Diskussionen
What is the difference between int, where I write under using namespace std; and then I write it after int main ( ) { };
0 Stimmen
1 Antwort
why it is not show any output when run this program
#include<iostream>
using namespace std;
int main(){
for(;;){
int i=0;
if(i==1){
cout<<i;
break;
}
++i;
}
1 Stimme
2 Antworten
#include <iostream>
using namespace std;
int main() {
int i;
for(i=1;i<=6;i+=3)
{
cout<<i;
}
return 0;
}
hello guys pls tell me the output
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2 Antworten
In my laptop I use #include<iostream.h>. Here while practice we use using namespace std. I get error if I use both in opposite platform. Why?
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2 Antworten
why this output 4 not 5;
#include<iostream>
using namespace std;
class A{
public:
int x=3;
A(){x++;}
~A(){x++;}
};
int main() {
A obj;
cout<<obj.x;
}
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2 Antworten
wt is output if a=2.0,b=2.5
#include <iostream>
using namespace std;
int main()
{
int a, b;
int sum;
cout << "Enter a number \n";
cin >> a;
cout << "Enter another number \n";
cin >> b;
sum = a + b;
cout << "Sum is: " << sum << endl;
return 0;
}
0 Stimmen
21 Antworten
why it is not show any output when run this program
#include<iostream>
using namespace std;
int main(){
for(;;){
int i=0;
if(i==1){
cout<<i;
break;
}
++i;
}}
0 Stimmen
2 Antwortenwhat is that output of this program
#include<iostream.h>
using namespace std;
int main()
{
int e1=5, e2=20, e3 = 15;
int *arr[ 3]= {&e1, &e2, &e3};
court<<*arr[*arr[1]-19];
return 0;
}
0 Stimmen
3 Antworten
why this output is 339 ???
#include<iostream>
using namespace std;
int x(int &a,int &b)
{
a=1;
b=3;
return a*b;
}
int main()
{
int a=3;
int b=4;
int c=x(b,b);
cout<<a<<b<<c;
}
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3 Antwortenwhy this program show compile error?
#include<iostream>
using namespace std;
class a{
public:
int f(){cout<<3;}
int f(int a){cout<<a;}
};
class b:public a
{
public:
int f(){cout<<5;}
};
int main()
{
b obj;
obj.f(7);
}
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4 AntwortenHi! can anyone help me to write this simple code: #include <iostream>
using namespace std;
int main()
{
if (7 > 4) {
cout << "Yes";
}
return 0;
}
into Microsoft Visual Studio 2015?
0 Stimmen
4 Antworten
#include <iostream>
using namespace std;
class employee
int main()
{
private:
double salary;
public:
void getsalary(double sal)
{
salary=sal;
}
void display()
{
cout<<"the salary:"<<salary;
}
};
void main ()
{
employee programmer;
employee manager;
manager.getsalary (60000.0);
programmer.getsalary(40000.0);
manager.display();
programmer.display();
return 0;
}
1 Stimme
5 Antworten
#include <iostream>
using namespace std;
int main()
{
int b[];
int i=0,sum=0;
while(cin>>b[i])
{sum=sum+b[i];
i++;}
cout<<sum<<endl;
}//what is wrong in this code
//how can I take multiple inputs into an array
//I want to take unknown no. Of inputs
0 Stimmen
4 Antworten
I wrote a simple basic c++ code in my PC notepad and I saved it with .cpp extension also. But when I run this program in any browser it shows the code as it is... Do c++ code can be written in notepad and can be run? Please answer.
#include <iostream>
using namespace std;
int main()
❴
cout << "hello";
return0;
❵
2 Stimmen
10 Antworten
why not this program output 7 and why it shows compiler error ???
#include<iostream>
using namespace std;
class a{
public:
int f(){cout<<3;}
int f(int a){cout<<a;}
};
class b:public a
{
public:
int f(){cout<<5;}
};
int main()
{
b obj;
obj.f(7);
}
1 Stimme
3 Antworten
Can someone help me please. I can understand the result of the cout << p << endl;
#include <iostream>
using namespace std;
int main() {
int x = 8;
int *p;
p = &x;
cout << *p << endl;
cout << p << endl;
cout << &p;
return 0;
}
1 Stimme
6 Antworten
in the following why the code num=num+1;can't be applied just after while loop in the beginning of curly braces?
#include <iostream>
using namespace std;
int main()
{
int num = 1;
while (num < 6) {
cout << "Number: " << num << endl;
num = num + 1;
}
return 0;
}
0 Stimmen
7 Antworten
can anyone explain this output?
#include <iostream>
using namespace std;
int x(int &a,int &b)
{
a=3;
b=4;
return a+b;
}
int main()
{
int a=2;
int b=7;
int c=x(a,a);
cout <<a<<endl<<b<<endl<<c;
}
output:-
4
7
8
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2 Antworten
ما هو الخطأ فى هذا الكود
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2 Antwortenwhich of the following statements are correct for accessing x?and why?
#include <iostream>
using namespace std;
class test{
public:
int x=9;
};
int main()
{
test t;
test *p=&t;
}
select all that apply:-
a) t.x
b) p.x
c) t->x
d) p->x
1 Stimme
3 AntwortenI don't understand how to comes following output???could anyone explain?
#include <iostream>
using namespace std;
int x(int &a,int &b)
{
a=3;
b=4;
return a+b;
}
int main()
{
int a=2;
int b=7;
int c=x(a,a);
cout <<a<<endl<<b<<endl<<c;
}
output:-
4
7
8
1 Stimme
2 AntwortenIn the code below the output is 2. This code is used in a challenge and I get an error when I select the answer 2. It accepts as correct the answer 1 which I believe is wrong. If you agree please thumbs up.
If you find any other errors please post them here!
#include <iostream>
using namespace std;
int main()
{
for(int i=1; i>=1; i++) {
if(i<1 || i>1){
cout << i;
break;
}
}
return 0;
}
8 Stimmen
8 Antworten
can anyone plz explain me this program step by step?#include <iostream>
using namespace std;
class MyClass {
public:
int var;
MyClass() { }
MyClass(int a)
: var(a) { }
MyClass operator+(MyClass &obj) {
MyClass res;
res.var= this->var+obj.var;
return res;
}
};
int main() {
MyClass obj1(12), obj2(55);
MyClass res = obj1+obj2;
cout << res.var;
}I am not getting the part inside operator+
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8 Antwortenwhy this output only comes 3 and why not output 123?
#include<iostream>
using namespace std;
class A{
public:
virtual void f(){cout<<1;}
};
class B:public A{
public:
void f(){cout<<2;}
};
class C:public B{
public:
void f(){cout<<3;}
};
int main()
{
B *p=new C;
p->f();
}
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3 Antwortenwhy does this code output that there is an error because the else statement doesn't have a corresponding if statement?. How do i correct this?
#include <iostream>
using namespace std;
int main() {
int a;
for (int x =0; x<5;x++){
cin>>a;
if (a<1){
cout<<"a cannot be less than 1\n";
}
else if (a>10){
cout <<"a cannot be greater than 10\n";
}
}
else{
cout<<"code can run now"<<endl;
}
return 0;
}
3 Stimmen
8 Antworten
if i download the programs for c++ on my pc ( codebuilds and the compiler ) and i want to write a program in my package ( workspace ) i create a new file and write smthing beginning
#include <iostream>
using namespace std;
int main ()
{
...
}
and i want to run it, it always runs this first program : Hello World. and not my written program how can i run just my written program ?
have i maybe to write anything else as
int main () {} ?
0 Stimmen
16 Antworten
what is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Stimme
7 Antworten
what is the size of operate? assume size of (int)=2
#include <iostream. h>
using namespace std ;
class test
{
int x_ ;
int y_;
} ;
int main() {
test t ;
court<<size of (t)<<" ;
}
-1 Stimme
2 Antwortencan someone please explain why this code keeps telling me complication error instead of outputting the value of speed.
#include <iostream>
using namespace std;
class myClass {
public:
void setcarspeed (int a){
speed=a;
}
int getcarspeed(){
return speed;
}
private:
int speed;
};
int main() {
myClass obj;
obj.setcarspeed (40);
cout<<obj.getcarspeed ;
return 0;
}
2 Stimmen
3 AntwortenWhat ever I learned here most of the things are not working in turbo c++ ? i.e . instead of iostrem I have to write iostream. h . why is this so?? also it is not accepting this- using namespace std;
. and also not accepting return 0; . Please help me iam really confused. Thanks :)
0 Stimmen
5 Antworten
using System;
namespace GoodProgrammerTest
{
class Program
{
static void Main(string[] args)
{
Console.Write("Enter Yes or No");
Console.Write(
"Do you programme every day? : ") ;
int answer = Console.ReadLine();
if (answer =="Yes")
{
Console.WriteLine(
"You will be a good programmer");
}
else
{
Console.WriteLine(
"You will not be a good programmer");
}
}
}
}
2 Stimmen
3 Antworten
where did the error go
0 Stimmen
1 Antwort
hey guys, I've been trying to work out the formula 'v=I*r'. But whenever I run the program and input values for I and r, it doesn't give the right answer.
This is the code
#include <iostream>
using namespace std;
int main() {
int i,r;
int v = i*r;
cout<<"what is the value of i?\n";
cin>>i;
cout<<"what is the value of r?\n";
cin>>r;
cout<<"voltage ="<<v<<endl;
return 0;
}
p/s: I'm new to programming
1 Stimme
8 Antworten#include <iostream>
using namespace std;
int sum(int a, int b=42) {
int result = a + b;
return (result);
}
int main() {
int x = 24;
int y = 36;
//calling the function with both parameters
int result = sum(x, y);
cout << result << endl;
//calling the function without b
result = sum(x);
cout << result << endl;
return 0;
}
why is da last function cout 66 and not 48 isn't it suppose to add 24+24?
1 Stimme
6 Antworten
Помогите с задачами
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1 AntwortHeute heiß
Help please?
4 Votes
Ejercicio Pytho
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What is that z for
0 Votes
Suggestions needed
4 Votes
Game development
0 Votes
Ruby programming?
3 Votes