F&A Diskussionen
i want to print sum of all integers from 1to 100 like for example :
1
3
6
10
15......
i tried it i know my code is wrong please help me class Program {
public static void main(String[] args) {
for(int x = 1; x <101; x++) {
int sum = int x;
System.out.println("1");
System.out.println("sum");
}
}
}
3 Stimmen
11 Antwortenwhat's wrong in this condition
prompt ("")
if (prompt ("1")) {
document.write("<h1>HTML Tutorial</h1>");
} else if (prompt ("2")) {
document.write("<h1>CSS Tutorial</h1>");
} else {
document.write("<h1>JavaScript Tutorial</h1>");
}
I want when type 1 in output HTML tutorial shows, type 2 css tutorial shows else javascript tutorial
0 Stimmen
13 AntwortenHi, I need assistance aka HELP!
I've done this calculation in various ways some of printed nothing but zeros non stop.
Using while loop calculate all numbers 1 to 1000 add numbers to sum = sum + i
int sum = 0;
// use a while loop to calculate the sum of 1 to 1000
While(int sum = 0; sum >= 1000; sum = sum + I){
System.out.println(sum);
}
0 Stimmen
4 AntwortenIn the code below the output is 2. This code is used in a challenge and I get an error when I select the answer 2. It accepts as correct the answer 1 which I believe is wrong. If you agree please thumbs up.
If you find any other errors please post them here!
#include <iostream>
using namespace std;
int main()
{
for(int i=1; i>=1; i++) {
if(i<1 || i>1){
cout << i;
break;
}
}
return 0;
}
8 Stimmen
8 Antworten
what have i to do, if i want that the program always writes for example :
0+1
1+2
3+3
6+4
10+5
15+6
...
because now it just writes
1
3
6
10
15
...
and maybe if it works, can i make then
0+1=1
1+2=3
3+3=6
6+4=10
#include <iostream>
using namespace std;
int main(){
int i;
int sum = 0;
for (i = 1; i <= 100; i++){
sum = sum+i;
cout<<sum<<endl;
}
cout<<sum;
return 0;
}
1 Stimme
5 Antwortenhow do I get line breaks?
name = input("What is your name?:")
print("Hiya, " + name)
age = int(input("Tell me your age:"))
year = str((2016 - age) + 100)
num = int(input("Enter a number between 1 and 50:"))
line = str((name + " will be 100 in the year " + year) * num)
print(\n line)
2 Stimmen
3 Antwortenso far in section 1 question 2 area all of the videos have been ads that if you skip the add it just brings up the questions you need to answer. also if you play the add all the way thru you get the same exact thing. luckily I'm using this as a refresher course but I would think if I didn't know anything about c++ then I could be pretty lost missing videos.
0 Stimmen
2 Antwortencan someone tell me how to make it impossible for a user to type a 'userchoice1[x]' value that does not range from 1 - 10.
If you also know a way I can make the user input another value for the 'userchoice1[x]' variable if it is less than 1, I'll appreciate you share the knowledge with me.
please see the short code below
1 Stimme
2 AntwortenHeute heiß
New code
1 Votes
How would you solve the part of the C# Intermediate code project that requires operator overloading?
0 Votes
Hello Everyone
0 Votes