Java cast num to type int

Question

I can't figure out how to cast num to int. My code works when user entering an integer, but when a float number entered it gives me :

Enter an integer: 4.4
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at Assignments.KeybInp.main(KeybInp.java:8)

Here is my code: https://code.sololearn.com/cep7rPdino9d/#java
I have to cast the result to int and display it. This is my first assignment and I stuck. Help me to move on, please! Regards!

Answer 1

Maybe you can change
int number = scanner.nextInt(); to
double number = scanner.nextDouble();
And change the type of value from double to int.

Answer 2

InputMismatchException was triggered because you try to assign a floating point number into an integer, @Jente's suggestion was right, you should be ready for such possibilities where integer was expected, yet floating points were given, and one of the ways to do that would be to use floating point type, which you can later try to cast to integer.

import java.util.Scanner;

public class KeybInp {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter an integer: ");

// Accept input as double in order to
// cope with floating point input possibility
double number = scanner.nextDouble();
scanner.close();

System.out.println("The number is: " + number);
System.out.println("The number converted to int " + (int)number);
}
}

Hth, cmiiw

Answer 3

Thank you for the reply! if I understanding correctly, int has to be a round number without a dot. It gives me for instance 7.0 while I need just 7

Answer 4

Ok, I did it! Thank you very much again! I changed int to double as you said and added (int) to System.println: System.out.println("The number is: " + (int)value);