How to keep an element in my array?

Question

I have a c++ code but I'm having a problem. I need to insert a value on my array [][] and then I print it. However I need to keep and show that value after that and insert another one. How can I do this ?

Answer 1

I don't really understand your question so I'm going to give an example of my best guess.
int s, a[] = {9, 5, 1, 0, 4, 2, 8, 6, 3, 7};
s = a[6]; // gets 8
a[6] = 10;
cout << s << a[6]; // outputs 8 & 10

If this isn't what you're asking, please give an example such as this one describing my code above:
put 9, 5, 1, 0, 4, 2, 8, 6, 3, 7 into an array
replace the current sixth position with 10
display both the original and new values of the sixth position yielding 8 & 10

Answer 2

char board[15][15]
cin >> position; // row & column
if (board[position.row][position.column] == ' ') {
cin >> letter;
// if good letter store in board[position.row][position.column]
} else {
cout << "space in use"

Answer 3

You could do:
string ARRAY[][] = {{"A","B","C"},{"D","E","F"},{"G","H","I"}};
This allocates ARRAY[3][3] with 9 values.

Answer 4

so array[playerNumber][word] type deal

Answer 5

Scrabble board[column][row] for the players move

Answer 6

@John Wells

What I mean, I'm giving the input for an string array so i give the positions

ARRAY[0][0]= "A" // I insert the value that I what there

all the values I need to insert them one by one
for example the next one could be

ARRAY [0][1] = "B"

And I need to keep holding both values

Answer 7

No that's not useful, It's an scrabble game actually only by compilation time I need to insert the values per player one by one in the position that they what
and the values the need.
thanks!

Answer 8

but I still to keep on the screen every value, that's the matter that I'm having
Only the last movement it's shown on the tablegame

Answer 9

I'll try
thank so much John