program in C++ to find the transpose of a given matrix

Answer 1

Scott is right it is simple store it in multi dimensional array and give rows into column and column into rows.
#include <iostream. h>

int main() {
int I,j, r,c;
int a[10][10], trans [10][10];
cout<<"Enter the no of rows and columns to be made";
cin>>r>>c;

// let's make the array
for(i=0;i<r;i++)
for (j=0;j<c;j++)
{
cout<<"Enter elements of <<i+1<<j+1;
cin>>a[i][j];
cout<<endl;
}
}
cout<<endl<<"Transpose of matrix";
// this will print the matrix
cout<<":"<<endl

for(i=0; i<r;++i)
for(j=0;j<c;j++)
{
cout<<" "<<a[i][j];
if (j==c-i)
cout<<endl;
}

// now transposing matrix
for(i=0;i<r;++i)
for(j=0;j<c;++j)
{
trans[i][j]=a[j][i]
}

cout<<endl<<"Transpose is this"
for(i=0;i<c;++i)
for(j=0;j<r;++j)
{
cout<< ""<<trans[i][j];
if(j==r-1)
cout<<endl;
}
return 0
}

I have learnt this program somewhere

Answer 2

I made this available on my profile so you can run it and try it out.

#include <iostream>

using namespace std;

int main ()
{
const int N = 3; // Size of the N by N matrix
int Matrix [N][N]; // Create matrix of N*N
int Transpose [N][N]; // Elements will be moved into the transpose matrix

/* Example matrix for demonstration*/

for (int i = 0; i < N; i++)
Matrix[0][i] = i + 1;
for (int i = 0; i < N; i++)
Matrix[1][i] = i + 4;
for (int i = 0; i < N; i++)
Matrix[2][i] = i + 7;

// Print out the matrix
for (int i = 0; i < N; i++)
{
cout << endl;
for (int j = 0; j < N; j++)
cout << Matrix[i][j] << ' ';
}
cout << endl;
/* */

// Transpose the N by N matrix we set up above
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
{
Transpose[j][i] = Matrix[i][j];
}

// Print the transposed matrix

for (int i = 0; i < N; i++)
{
cout << endl;
for (int j = 0; j < N; j++)
cout << Transpose[i][j] << ' ';
}
cout << endl;

return 0;
}

Answer 3

Here is the code snippet to find transpose of a matrix :
/* transpose[i][j] = inputMatrix[j][i] */
for(rowCounter = 0; rowCounter < rows; rowCounter++){
for(colCounter = 0; colCounter < cols; colCounter++){
transposeMatrix[colCounter][rowCounter] = inputMatrix[rowCounter][colCounter];
}
}

Source : http://www.techcrashcourse.com/2015/03/c-program-to-find-transpose-of-matrix.html
http://www.techcrashcourse.com/2016/04/cpp-program-find-transpose-matrix.html