Stupid question

Question

#include <iostream>
#define X 5+2
using namespace std;

int main() {
cout << X <<endl;
cout <<X*X<<endl;
int i =X*X*X;
cout<< i;
return 0;
}

output: 7
17
27

why isn't the output
7
49
343

Thanks

Answer 1

5 + 2 * 5 + 2 = 17
5 + 2 * 5 + 2 * 5 + 2 = 27

Answer 2

link to the code

https://code.sololearn.com/cMNUXrpoGO0W/?ref=app

Answer 3

Macros simply do text substitution. They will not care about the operator precedence. As long as 'X' is a single operand there is no problem. If you want to be safe, It is better to enclose #define expressions in brackets like the following

#define X (5+2)

Answer 4

Maybe,the trick is to add the multiplication first ?

Answer 5

thanks @vulcan

Answer 6

yeah i think so

Answer 7

The answer which has given by Android above is correct.Here X is initialize to 5+2,so the value of X is 5+2 not 7. Then by putting this value you will get the answer correctly.