This is stuck in an infinite loop

Question

#include <iostream>
using namespace std;

int main() {
int k = 0;
enum CompanyRole {EXECUTIVE = 1, MANAGER = 2, STAFF = 3};

cin >> k;
while((k != 1) || (k!=2) || (k!=3)){
switch(k)
{
case EXECUTIVE:
cout << "Executive\n";
break;
case MANAGER:
cout << "Manager\n";
break;
case STAFF:
cout << "Staff\n";
break;
default:
cout << "Wrong role. Enter again.\n";
break;

}
std::cin >> k;
}

return 0;

Answer 1

Do you want to exit from the while loop with a switch case?

Answer 2

Move the switch out of the while loop

Answer 3

when I type in 1-3, I want it to print the corresponding message and stop there. when I type in any other number, I want it to loop until I type 1-3

Answer 4

my instructions call for the switch case to be inside a while loop

Answer 5

Try to put cin >> k inside the default switch case, before the break

Answer 6

1, 2, 3 still cause infinite loop. And I am getting time limit exceeded

Answer 7

I would make a boolean allow =True as while condition.
boolean allow = true;
While(allow) {
cin>>k;
switch (k) {
Case 1:
cout << "Case1;
allow = false; //to break the loop, same with case 2-3
}
}

Answer 8

so I have this: 1-3 works good now, other numbers cause indefinite loop

#include <iostream>
using namespace std;

int main() {
int k = 0;
enum CompanyRole {EXECUTIVE = 1, MANAGER = 2, STAFF = 3};
bool allow = true;
while(allow) {
cin>>k;
switch (k) {
case 1:
cout << "Case1 \n";
allow = false;
break;
case 2:
cout << "Case2 \n";
allow = false;
break;
case 3:
cout <<"Case3 \n";
allow = false;
break;
default:
cout << "try again \n";
cin >> k ;
break;//to break the loop, same with case 2-3

std::cin >> k;
}
}
return 0;
}

Answer 9

Remove the cin>>k inside the switch, you are also waiting for user input at starting of each while loop