Can someone explain the code step by step?

Question

public class MyClass {
public static void main(String[ ] args) {
int x = 5;
addOneTo(x);
System.out.println(x);
}

static void addOneTo(int num) {
num = num + 1;
}
}

Answer 1

You're defining a public class "MyClass". Inside it. You're defining two static methods(main, addOne). Normally static void main is the entry point for executing a Java program. Assuming you execute main method: You're declaring an int variable (x) and initializing it's value with 5. Then you're calling addOneTo method. AddOneTo is a method that increments input parameter (int) value by one, but it doesn't return its value. So you are declaring x variable and then you're printing it's value. That's it!

int x = 5 -> initialices int variable x on 5
addOneTo(x) -> Increments x from 5 to 6 But when exiting this method, x remains 5 on main method because the variable's Scope. X it's defined only for main method, is not a class attribute and addOneTo method does not return this value, so it will be eventually lost.

System.out.println(x); -> Prints 5

Hope I helped you. Have a nice day and enjoy coding!!

Answer 2

public class MyClass {
public static void main(String[ ] args) {
int x = 5;
x=addOneTo(x);
System.out.println(x);
}

static int addOneTo(int num) {
return num + 1;
}
}

//this will output 6 , u will see 👉3 modifications
//be simple , hopu U got the difference & also understood why output was 5 in the previous code👍

Answer 3

//variable of type integer declaration
int x=5;
//function increments x by one
addone(x){ x=x+1; therefore x=6 }
//outputs x which is 6
System.out.println(x)

Answer 4

Why is the method addOne used if 5 + 1 would be 6?

Answer 5

So there is a mistake in the course: Java/Classes and Objects/Value & Reference Types lesson 1. Could you have a look?

Answer 6

So the output is 5, but why?