Char pointer / i dont understand the output

Question

char *var = "hello";
char *p = var;
cout<<var; // outputs hello
cout <<p; // outputs hello
cout <<*p; // outputs h

i dont understand why dont output this code addresses in memory? location?
it seems to me different from int type pointets working. HELp.

Answer 1

if you want to see address in Memory change it to
cout<<&p;
this code show you address of var character.

Answer 2

write down code which i mentioned above you will see hex...

Answer 3

but how can be the address of var hello and not a hex??

Answer 4

oke, thanks, i am so confusing with this char pointer behavior.

Answer 5

chars are treated differently in c++ than other data types.