Code challenge

Question

check the given number is even or odd without using %, *, / operator....

Answer 1

submit it as an assignment in lesson factory

Answer 2

Please submit this as an assignment in the Lesson Factory
https://www.sololearn.com/discuss/1082512/?ref=app

Answer 3

print("Odd" if int(input())&1 else "Even")

print(["Even", "Odd"][int(input())&1])

Answer 4

https://code.sololearn.com/cyTguvG8bo7q/?ref=app

Answer 5

ok

Answer 6

check in code playground ...already submitted

Answer 7

if (num % 2 == 0) cout << "Even";
else cout << "Odd";

//Or

cout << (num % 2 == 0) ? "Even" : "Odd";

//Or

cout << (!(num%2)) ? "Even" : "Odd";

//Or

cout << (num%2) ? "Odd" : "Even";