#include<stdio.h> int main(){ int i=2,j=2; while(i+1?–i:j++) printf(“%d”,i); return 0; }

Question

what will be the output?

Answer 1

while loop is wrong. check the C++ course and change it.

Answer 2

just change one thing you'll get an answer..

Answer 3

if anyone of you interested, just solve this code.. print the output as 1..

Answer 4

I know it is.. but someone have knowledge about this.. if you are the person who someone.. you can solve this..

Answer 5

Output: 1

Consider the while loop condition: i + 1 ? — i : ++j

In first iteration:

i + 1 = 3 (True)

So ternary operator will return -–i i.e. 1

In c 1 means true so while condition is true. Hence printf statement will print 1

In second iteration:

i+ 1 = 2 (True)

So ternary operator will return -–i i.e. 0

In c zero means false so while condition is false. Hence program control will come out of the while loop.

Answer 6

The while loop will always be true umm..

Answer 7

Output will be 22222... and it is infinite loop.....

since the while condition is conditional operator it performs the logic without terminating .
The print statement is i, where i is 2...it doesnt changes since we didn't assign it ...Is this correct I also executed

Answer 8

WHAT have u created an error mess

Answer 9

And so it will go in infinite loop and will print 2 infinitely

Answer 10

Idk