write a program that input an integer and passes it to function.The function should return the number of digits in that number .

Question

Example.. if the integer is 68 .Then function should return 2.

Answer 1

#include <iostream>
using namespace std;
int func(int num){
int count=0;
while(num)
{
num/=10;
count++;
}
return count;
}
int main() {
int num,c;
cout<<"Enter a number\n";
cin>>num;
c=func(num);
cout<<c;
return 0;
}

Answer 2

@Hussain
I will explain with an example
assume it's a 3 digit number 456
initially count is 0

in 1st iteration
456 is divided by 10 and becomes a 2 digit number 45. count becomes 1

in 2nd iteration
45 is divided by 10 and becomes a 1 digit number 4. count becomes 2

in 3rd iteration
4 is divided by 10 and becomes a 0 . count becomes 3 and it exits the loop.

Answer 3

#include <iostream>
using namespace std;

int num_dig(long long num)
{
int digits(1);

while(!(num> >= 0 && num < 10) )
{
num /= 10;
++digits;
}

return digits;
}
int main()
{
long long num = 54375;
cout << num << " has " << num_dig(num) << " digits";
return 0;
}

Answer 4

#Midhun_mathew its a fine code but i can't understand [ num/=10
and count++ ] when i'm enter 3 digit number then how it's work

plz guide me its really helpfull for me thanks

Answer 5

@Mathew thanks JAZAKALLAH

Answer 6

@Mathew thanks JAZAKALLAH

Answer 7

@Elio your code not run in Dev C++! plz re check Thanks

Answer 8

what's the error you get? it could be this line int digits (1); change to int digits = 1;