Output finding

Question

n=5;
if(n=0)
cout<<"zero";
else
cout<<"non zero ";
cout<<endl;
cout<<n;
what should be the output?

Answer 1

Mistake is in your if condition
if(n=0) is wrong

if(n==0) is right.

You have missed single = sign in condition.

Based on your condition n=0 is always right because you're just assigning and it always be true.

Hope you understand this

Answer 2

I don't know what you mean. Here, let me explain it like this...

int n = 5;
if (n = 0)
cout << "is 0\n";
else
cout << "not 0\n";
cout << n;

/*
output is:
is 0
0
*/

int n = 5;
if (n == 0)
cout << "is 0\n";
else
cout << "not 0\n";
cout << n;

/*
output is:
not 0
5
*/

Answer 3

The way an if statement works, is that it will run if a condition evaluates to true. Similarly, the else statement will run if a statement evaluates to false.

If you wasn't already aware, 0 represents FALSE, and any other number reresents TRUE. Therefore...

if (1) { }

is perfectly valid, and will run 100% of the time, because 1 is a constant which will evaluate to TRUE.

When you use...

if (n = 0) { }

you are setting n to 0, which is FALSE, therefore the else block will run.

When you use...

if (n == 0) { }

you are checking whether or not n is equal to zero. If it is, it's true. If it's not, it's false.

Answer 4

You are setting n to 6.

6 is true as it is a non-zero value, therefore the if statement runs.

Answer 5

Yes. I know what the output is, and I know why it is outputting that.

What is your question?

Answer 6

No. Inside the if statement you use the conditional operator (==). If you use the assignment operator (=), you are changing the value of n, which I'm assuming is what you don't want.

Answer 7

if we use = operator instead of == operator then
will we not face any type of error?
if no error occured then why do we say that if is a conditional statement?

Answer 8

Whether you use the assignment operator or the conditional operator inside the if statement, no compile errors will come up, as they are both valid.

The implimentation is what changes. = is assigning the value of n to something else. == is checking the value of n against something else.

Answer 9

if we can use assignment statement statement in if statement then why do we say if as conditional statement?

Answer 10

#include <iostream>
using namespace std;

int main() {
int n=5;
if(n=6)
cout<<"six ";
else
cout<<"zero ";
cout<<endl<<n;
return 0;
}

run then you will see if n=6 then also same problem exists.why?

Answer 11

output should be:
non zero
0

but how?

Answer 12

You are using the assignment operator (=). Use the conditional operator (==).

What you're doing, is assigning n to 0 in the if statement, which is false, therefore the else blocks runs. After that, the value of n is printed, which is 0.

Answer 13

this (=)sign is in question and there is no error occured also.
you can also try this.

Answer 14

No. It's not an error, it does work like I explained. It's not working for what you want though. You don't want me be ASSIGNING n to 0 in the if statement, you want to be checking it's CONDITION. Hence the conditional operator (==).

Answer 15

but in qestion output is based on given conditions not on our condition .
you can also run it and can check the output.

Answer 16

output of this question result in the below output as you can also check it by running code. Bro
output:
non zero
0

Answer 17

my question is that according to this output.
shall we use assigning operator in 'if' statement condition part?

Answer 18

oooh thanks for clearing my doubt.☺👌👌💐