What does the following line of code do?

Question

// Please help me understand this line of code. Is the result the same for all computers?

cout << *(int*)const_cast<char*>("\x00\x01") & 1;

Answer 1

Maybe this explains it:
https://code.sololearn.com/cQhZf14d7KG0/?ref=app

Answer 2

Whoever wrote this line is an absolute fan of type casting.
const char* with hex values -> char* -> int* -> dereference and all that just to perform a bitwise AND with 1 which results in 0.