Can you use a function Output as an Input in a different function

Question

So, I was wondering if there was a way I could take the output of the bottom two functions to replace the x and y inside number_checker(x,y) whenever I call on it.

def number_checker(x,y):
if x == y:
print("Answer: Correct.\n")
if x < y:
print("Answer: Incorrect. Guess Lower.\n")
if x > y:
print("Answer: Incorrect. Guess Higher.\n")

def random_digit():
import random
random.randint(0, 9)

def guess_digit():
print(input("Enter a digit: \n"))

Answer 1

Have you tried? Always try. And the answer is yes. You just have to put their outputs in variables and use those variables as arguments when calling the first... And I would advice putting import random outside the function... Happy coding!!! ☺

Answer 2

Thanks for the help guys, I'm new to programming so this helped me a lot.

Answer 3

return function is the way to go

import random

def random_digit():
y = random.randint(0, 9)
return y

this = random_digit()

Answer = False

while not Answer:
def number_checker(x, y):
global Answer
if x == y:
print("Answer: Correct.\n")
Answer = True
if x < y:
print("Answer: Incorrect. Guess Higher.\n")
if x > y:
print("Answer: Incorrect. Guess Lower.\n")

def guess_digit():
y = this
x = int(input("Enter a digit:"))
return number_checker(x, y)

guess_digit()

Answer 4

def number_checker(x, y):
if x == y:
print("OK\n")
return 1
if x > y:
print(">")
return 0
if x < y:
print("<")
return 0

def guess_digit():
return input("Enter a digit: ")

def random_digit():
import random
return random.randint(0, 9)

rand = random_digit()

print rand

while 1:
if number_checker(guess_digit(), rand):
break