What is happening on line printf plzz explain

Question

https://code.sololearn.com/cCqfUTr9gizP/?ref=app

Answer 1

Arman khosla in C and C++, 1 = true, 0 = false.

For i=1,
1%2 = 1, hence true and i is printed (1).

For i=2,
2%2 = 0, hence false and i*2 is printed (2*2 =4).

For i=3,
3%2 = 1, hence true and i is printed (3).

Output: 143

Answer 2

It's called "ternary" operator.

The statement before '?' is the conditon and the 2 values on the left and right are the values to print based on true or false.

If the condition is true left is printed,
If it's false right is prinred.

Answer 3

Happy to help, feel free to ask any questions bro Arman khosla .

Answer 4

? is a short form of if statement,
(i%2) ? i : i*2
so the expression before is checked to see if its true or false (in this case it checks if its even) like in a normal if statement, the first expression will happen if its true (1+ which in this case would be odd) so the program prints i untouched, second one after the colon (:) is the expression that will happen if the program is false (0), so if the number is even it will be doubled

Answer 5

ooh thank you bro i understood😃