print 1 to end square of numbers in c

Question

using function in c write a program to 1 to end(entered by user) square of numbers.

#include<stdio.h>
int square(int x);
int main()
{
int n,i,s;
printf("Enter the value of n");
scanf("%d",&n);
printf("%d",square(i));
}
int square(int i){
int n,s;
for(i=1;i<=n;i++){
s=i*i;
printf("%d %d",i,s);
}
}

Answer 1

I've added comments to point out issues.
#include<stdio.h>
int square(int x);
int main()
{
int n,i,s; // s is never used
printf("Enter the value of n");
scanf("%d",&n);
printf("%d",square(i)); // i hasn't been assigned
}
int square(int i){
int n,s;
for(i=1;i<=n;i++){ // n hasn't been assigned
s=i*i;
printf("%d %d",i,s);
}
} // Failed to return a value so garbage will be printed