Task about #define x 5+2 in C++ battle

Question

There is following task in C++ battle.
We have the code:
#define x 5+2
void main()
{
cout x*x*x;
}
And there is question: what output will be?
I thought that x=7 and so output is 7^3=343. But right answer is 27.
Please, explain why output is 27.
https://code.sololearn.com/c31k0ji5URfW/?ref=app

Answer 1

Multiplication has higher precedence than addition. So in your case:
5+2*5+2*5+2 evaluates to 27
thats the nasty nature of #define I would suggest using constexpr instead.

Answer 2

Try adding the line:
cout << 5 + 2 * 5 + 2 * 5 + 2;

And see what result you get.

Answer 3

Like Kuba H has said..
cout << 5 + 2 * 5 + 2 * 5 + 2;
Becomes
cout << 5 + 10 + 10 + 2;

Answer 4

Keep in mind that #define does not evaluate the expression it just copy paste it.

Answer 5

Thank you jay and Kuba H.