+ 3
Could I use: $VAR = [1, 2, 3, 4]; for arrays
8 Answers
+ 7
you must use
$VAR = (1, 2, 3, 4 );
for your array
+ 4
syntext error.
+ 3
No you can't.
+ 2
$var=array(1,2,3,4);
+ 1
no you can't
$var=array(1,2,3,4);
0
where is array ?
you need to declare it
0
yes, learn php7
- 4
S