C dynamic memory

Question

//i want create dynamic array with 3 int
int *x = (int *)calloc(3, sizeof(int));

//set the first array member
*x = 10;
//set the sixth array member
*(x+5) = 20;

std::cout << *(x+5); //output: 20

the questions:

is there another way to set array member? i hope i can using [] and not using arithmetic operation

how can i set 6th member of array while i just set 3 in calloc and i can access it too?

Answer 1

thanks

Answer 2

ofc mate, here:
int* arr = new int[size];
remember to delete it afterwards when you are done with it.
And you refer to it as arr[0], arr[1] etc

Answer 3

@Paul

i know that using new. but using malloc or calloc with []?

Answer 4

I do not think that zi get the question. You want to create such a thing but without new, just using one of those?

Answer 5

have you tried using something like that tho?
int* arr = malloc(2*sizeof(int));
arr[0] = 3;
arr[1] = 9;
etc..
?