+ 3

Hey, i want to create a questionnaire using a code. Can you help me?

the questionnaire will use user input. if the user inputs very tall, for example, it must return a description. else if the user inputs short, it must return a different description. can you help me by telling me what code should I use? I think it will make everyone laugh, smile and wonder.

17th Dec 2016, 5:58 PM
Edwin Pratt
Edwin Pratt - avatar
3 Answers
+ 4
in JavaScript : get input in var (e.g. x) then check length property (e.g. x.length < 5 || x.length > 10).....
17th Dec 2016, 6:00 PM
Valen.H. ~
Valen.H. ~ - avatar
+ 2
create a header file in c++ and/or a class which outputs a description. for example: #include <iostream> #include <very_tall.h> using namespace std; int main ( ) cout << you are very tall << endl return 0; if very tall { very tall::very_tall. h } or class very tall { cout << you are very tall << endl return 0; } if very tall { very tall::very tall }
17th Dec 2016, 6:17 PM
Edwin Pratt
Edwin Pratt - avatar
+ 1
this is my c++ code~ string heights; cout << "Wanna hear a joke??\n" << endl; //intro cout << "If you're tall then enter 'tall' ..\n"; cout << "And if you're short then enter 'short'\n\n\n"; cin >> heights; //gets user inputs if (heights == "short") { //a joke for tall people so that short people can laugh cout << "\n\n\nWhat does a tall person do when they see an airplane coming? Duck." << endl; //You can use any jokes you want cin.ignore(); cin.get(); } else if (heights == "tall") { //a joke for short people so that tall people can laugh cout << "\n\n\nWhy do midgets always laugh when they play soccer? Because the grass tickles their balls." << endl;//You can use any jokes you want cin.ignore(); cin.get(); } else { cout << "Can't Recognize your height -!@#$%!#($#@
amp;*)-" << endl; //outputs error when user input anything besides their height } cout << "\n\n\nHave a nice day!!!\n\n\n" << endl;//finish
17th Dec 2016, 7:14 PM
Fluffy Rabbit
Fluffy Rabbit - avatar